(z+5i)(4+2i)-(z+2)(4+2i)=24+2i

2 min read Jun 17, 2024
(z+5i)(4+2i)-(z+2)(4+2i)=24+2i

Solving the Complex Equation: (z+5i)(4+2i)-(z+2)(4+2i)=24+2i

This article will guide you through the steps to solve the complex equation: (z+5i)(4+2i)-(z+2)(4+2i)=24+2i.

Let's break it down:

Simplifying the Equation

  1. Distribute: Expand the products on both sides of the equation:

    • (z+5i)(4+2i) = 4z + 2zi + 20i - 10
    • (z+2)(4+2i) = 4z + 2zi + 8 + 4i
  2. Substitute: Substitute the expanded products back into the original equation:

    • (4z + 2zi + 20i - 10) - (4z + 2zi + 8 + 4i) = 24 + 2i
  3. Simplify: Combine like terms:

    • 16i - 18 = 24 + 2i

Solving for z

  1. Isolate i terms: Subtract 2i from both sides and add 18 to both sides:

    • 14i = 42
  2. Solve for i: Divide both sides by 14:

    • i = 3
  3. Substitute i back: Since we know i = 3, there is no 'z' term in the equation, meaning there is no solution for 'z'.

Conclusion:

The equation (z+5i)(4+2i)-(z+2)(4+2i)=24+2i has no solution for 'z'. This is because the equation simplifies to an equation with only 'i' terms, and there is no 'z' term to solve for.

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