(3i)(-2i)(4i)

2 min read Jun 16, 2024
(3i)(-2i)(4i)

Multiplying Complex Numbers: (3i)(-2i)(4i)

This article will guide you through the process of multiplying the complex numbers (3i)(-2i)(4i).

Understanding Complex Numbers

Complex numbers are numbers that can be expressed in the form a + bi, where 'a' and 'b' are real numbers and 'i' is the imaginary unit, defined as the square root of -1 (i² = -1).

Multiplying Complex Numbers

When multiplying complex numbers, we follow the same rules as with regular multiplication, but we need to keep in mind the special property of 'i':

  • i² = -1

Solving (3i)(-2i)(4i)

  1. Multiply the first two factors: (3i)(-2i) = -6i²
  2. Substitute i² with -1: -6(-1) = 6
  3. Multiply the result with the remaining factor: 6(4i) = 24i

Therefore, the product of (3i)(-2i)(4i) is 24i.

Key Points

  • Remember the special property of 'i': i² = -1
  • Treat complex number multiplication like regular multiplication, but be mindful of the 'i' term.
  • The result of multiplying the given complex numbers is a purely imaginary number, 24i.

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