(4x+7)^2=44

2 min read Jun 16, 2024
(4x+7)^2=44

Solving the Equation (4x + 7)² = 44

This equation involves a squared term, which means we need to follow specific steps to solve for x.

1. Expand the Squared Term

First, expand the left side of the equation by using the FOIL method (First, Outer, Inner, Last) or by recognizing the square of a binomial pattern:

(4x + 7)² = (4x + 7)(4x + 7) = 16x² + 56x + 49

Now our equation looks like this: 16x² + 56x + 49 = 44

2. Transform into a Quadratic Equation

To solve for x, we need to transform the equation into a standard quadratic form, where one side equals zero:

16x² + 56x + 5 = 0

3. Solve the Quadratic Equation

We can solve this quadratic equation using the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

Where:

  • a = 16
  • b = 56
  • c = 5

Substitute the values into the formula and simplify:

x = (-56 ± √(56² - 4 * 16 * 5)) / (2 * 16)

x = (-56 ± √(2736)) / 32

x = (-56 ± 52.3) / 32

This gives us two possible solutions:

  • x₁ = -0.115
  • x₂ = -3.266

Conclusion

Therefore, the solutions for the equation (4x + 7)² = 44 are x = -0.115 and x = -3.266.

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