(x^(2)+3x)(2x+3)-16(2x+3)/(x^(2)+3x) =0

4 min read Jun 17, 2024
(x^(2)+3x)(2x+3)-16(2x+3)/(x^(2)+3x) =0

Solving the Equation: (x^(2)+3x)(2x+3)-16(2x+3)/(x^(2)+3x) =0

This equation presents a challenge due to its fractional form and the presence of a common factor. Let's break down the steps to solve it:

1. Factor out the Common Factor:

Notice that (2x+3) appears in both terms of the equation. Let's factor it out:

(2x+3) * [(x^(2)+3x) - 16/(x^(2)+3x)] = 0

2. Simplify the Expression Inside the Brackets:

To simplify further, let's get a common denominator for the terms inside the brackets:

(2x+3) * [(x^(2)+3x)(x^(2)+3x)/ (x^(2)+3x) - 16/(x^(2)+3x)] = 0

Now, we can combine the numerators:

(2x+3) * [(x^(4) + 6x^(3) + 9x^(2) - 16)/(x^(2)+3x)] = 0

3. Solve for Possible Values of x:

For the entire expression to equal zero, at least one of the factors must be zero. This gives us two possibilities:

a) (2x+3) = 0

Solving for x, we get: x = -3/2

b) (x^(4) + 6x^(3) + 9x^(2) - 16) = 0

This is a quartic equation, which can be difficult to solve directly. We can explore methods like factoring by grouping or using numerical methods to find approximate solutions.

4. Checking for Validity:

It is crucial to check if the solutions we find are valid. We need to ensure that the denominator (x^(2)+3x) is not zero for any of the solutions.

If we substitute x = -3/2 into the denominator, we get:

(-3/2)^(2) + 3 * (-3/2) = 9/4 - 9/2 = -9/4

This is not equal to zero, so x = -3/2 is a valid solution.

For the solutions obtained from the quartic equation, we need to ensure that the denominator is not zero as well.


The equation (x^(2)+3x)(2x+3)-16(2x+3)/(x^(2)+3x) =0 has at least one solution: x = -3/2. It may have other solutions depending on the solutions of the quartic equation. Remember to check the validity of all solutions by ensuring the denominator is not zero.

Featured Posts