Solving the Quadratic Equation: (x+4)(x-3)+(x-5)(x+4)=0
This article will guide you through the steps to solve the quadratic equation: (x+4)(x-3)+(x-5)(x+4)=0.
Step 1: Factor out the Common Term
Notice that both terms in the equation share the common factor (x+4). We can factor it out:
(x+4)(x-3) + (x-5)(x+4) = 0
(x+4)[(x-3) + (x-5)] = 0
Step 2: Simplify the Expression
Simplify the expression inside the brackets:
(x+4)(2x - 8) = 0
Step 3: Apply the Zero Product Property
The Zero Product Property states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we have two possible solutions:
- x + 4 = 0
- 2x - 8 = 0
Step 4: Solve for x
Solve each equation for x:
- x = -4
- x = 4
Conclusion
Therefore, the solutions to the quadratic equation (x+4)(x-3)+(x-5)(x+4)=0 are x = -4 and x = 4.