(x%2B3)(x-5)-in-standard-form.jpeg "(x+6)(x+3)(x-5) In Standard Form")
Expanding (x+6)(x+3)(x-5) into Standard Form
This problem involves expanding a product of three binomials into a polynomial in standard form. Here's how to do it:
1. Multiply the first two binomials:
(x+6)(x+3) = x² + 3x + 6x + 18 = x² + 9x + 18
2. Multiply the result from step 1 with the third binomial:
(x² + 9x + 18)(x-5) = x³ - 5x² + 9x² - 45x + 18x - 90
3. Combine like terms:
x³ - 5x² + 9x² - 45x + 18x - 90 = x³ + 4x² - 27x - 90
Therefore, the standard form of the polynomial (x+6)(x+3)(x-5) is x³ + 4x² - 27x - 90.