Simplifying the Expression: (x-1)^3 - (x+2)(x^2 - 2x + 4) + 3(x+4)(x-4)
This article will guide you through simplifying the given algebraic expression: (x-1)^3 - (x+2)(x^2 - 2x + 4) + 3(x+4)(x-4).
Step 1: Expand the Cubed Term
We begin by expanding the cubed term, (x-1)^3, using the binomial theorem or by repeated multiplication:
(x-1)^3 = (x-1)(x-1)(x-1) = (x^2 - 2x + 1)(x-1) = x^3 - 3x^2 + 3x - 1
Step 2: Expand the Products Using the Difference of Cubes and Difference of Squares Formulas
The expression (x+2)(x^2 - 2x + 4) represents the sum of cubes, and (x+4)(x-4) represents the difference of squares. We can utilize the following formulas:
- Sum of Cubes: a^3 + b^3 = (a+b)(a^2 - ab + b^2)
- Difference of Squares: a^2 - b^2 = (a+b)(a-b)
Applying these formulas, we get:
- (x+2)(x^2 - 2x + 4) = x^3 + 8
- 3(x+4)(x-4) = 3(x^2 - 16) = 3x^2 - 48
Step 3: Substitute and Combine Like Terms
Now, substitute the expanded terms back into the original expression:
(x-1)^3 - (x+2)(x^2 - 2x + 4) + 3(x+4)(x-4) = (x^3 - 3x^2 + 3x - 1) - (x^3 + 8) + (3x^2 - 48)
Combine the like terms:
= x^3 - 3x^2 + 3x - 1 - x^3 - 8 + 3x^2 - 48
= 3x - 57
Conclusion
Therefore, the simplified form of the expression (x-1)^3 - (x+2)(x^2 - 2x + 4) + 3(x+4)(x-4) is 3x - 57.