(−1−3i)⋅(−1+i)

2 min read Jun 17, 2024
(−1−3i)⋅(−1+i)

Multiplying Complex Numbers: A Step-by-Step Example

This article will demonstrate how to multiply two complex numbers, specifically (−1−3i)⋅(−1+i).

Understanding Complex Numbers

Complex numbers are numbers of the form a + bi, where 'a' and 'b' are real numbers, and 'i' is the imaginary unit, defined as √-1.

Multiplying Complex Numbers

To multiply complex numbers, we use the distributive property (also known as FOIL method) just like we do with binomials.

1. Expand the product:

(-1 - 3i) ⋅ (-1 + i) = (-1)⋅(-1) + (-1)⋅(i) + (-3i)⋅(-1) + (-3i)⋅(i)

2. Simplify:

1 + i + 3i + 3i²

3. Substitute i² with -1:

1 + i + 3i + 3(-1)

4. Combine real and imaginary terms:

(1 - 3) + (1 + 3)i

5. Final Result:

(-1−3i)⋅(−1+i) = -2 + 4i

Conclusion

Therefore, the product of (-1 - 3i) and (-1 + i) is -2 + 4i. This process demonstrates how to multiply complex numbers using the distributive property and understanding the properties of the imaginary unit 'i'.

Related Post